TSTP Solution File: NUM668^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : NUM668^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n065.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:22 EST 2018

% Result   : Theorem 0.44s
% Output   : Proof 0.44s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM668^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.03  % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.02/0.23  % Computer : n065.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.625MB
% 0.02/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Jan  5 12:13:34 CST 2018
% 0.02/0.23  % CPUTime  : 
% 0.02/0.24  Python 2.7.13
% 0.44/0.67  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.44/0.67  FOF formula (<kernel.Constant object at 0x2afad846dcb0>, <kernel.Type object at 0x2afad846d758>) of role type named nat_type
% 0.44/0.67  Using role type
% 0.44/0.67  Declaring nat:Type
% 0.44/0.67  FOF formula (<kernel.Constant object at 0x2afad8114d40>, <kernel.Constant object at 0x2afad846dfc8>) of role type named x
% 0.44/0.67  Using role type
% 0.44/0.67  Declaring x:nat
% 0.44/0.67  FOF formula (<kernel.Constant object at 0x2afad846d638>, <kernel.Constant object at 0x2afad846dfc8>) of role type named y
% 0.44/0.67  Using role type
% 0.44/0.67  Declaring y:nat
% 0.44/0.67  FOF formula (<kernel.Constant object at 0x2afad846dcb0>, <kernel.DependentProduct object at 0x2afad846dcf8>) of role type named pl
% 0.44/0.67  Using role type
% 0.44/0.67  Declaring pl:(nat->(nat->nat))
% 0.44/0.67  FOF formula ((forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0))))->False) of role conjecture named satz18
% 0.44/0.67  Conjecture to prove = ((forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0))))->False):Prop
% 0.44/0.67  We need to prove ['((forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0))))->False)']
% 0.44/0.67  Parameter nat:Type.
% 0.44/0.67  Parameter x:nat.
% 0.44/0.67  Parameter y:nat.
% 0.44/0.67  Parameter pl:(nat->(nat->nat)).
% 0.44/0.67  Trying to prove ((forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0))))->False)
% 0.44/0.67  Found eq_ref00:=(eq_ref0 ((pl x) y)):(((eq nat) ((pl x) y)) ((pl x) y))
% 0.44/0.67  Found (eq_ref0 ((pl x) y)) as proof of (((eq nat) ((pl x) y)) ((pl x) Xx_0))
% 0.44/0.67  Found ((eq_ref nat) ((pl x) y)) as proof of (((eq nat) ((pl x) y)) ((pl x) Xx_0))
% 0.44/0.67  Found ((eq_ref nat) ((pl x) y)) as proof of (((eq nat) ((pl x) y)) ((pl x) Xx_0))
% 0.44/0.67  Found ((eq_ref nat) ((pl x) y)) as proof of (((eq nat) ((pl x) y)) ((pl x) Xx_0))
% 0.44/0.67  Found (x00 ((eq_ref nat) ((pl x) y))) as proof of False
% 0.44/0.67  Found ((x0 y) ((eq_ref nat) ((pl x) y))) as proof of False
% 0.44/0.67  Found (fun (x0:(forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0)))))=> ((x0 y) ((eq_ref nat) ((pl x) y)))) as proof of False
% 0.44/0.67  Found (fun (x0:(forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0)))))=> ((x0 y) ((eq_ref nat) ((pl x) y)))) as proof of ((forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0))))->False)
% 0.44/0.67  Got proof (fun (x0:(forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0)))))=> ((x0 y) ((eq_ref nat) ((pl x) y))))
% 0.44/0.67  Time elapsed = 0.157441s
% 0.44/0.67  node=21 cost=-56.000000 depth=7
% 0.44/0.67::::::::::::::::::::::
% 0.44/0.67  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.44/0.67  % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.44/0.67  (fun (x0:(forall (Xx_0:nat), (not (((eq nat) ((pl x) y)) ((pl x) Xx_0)))))=> ((x0 y) ((eq_ref nat) ((pl x) y))))
% 0.44/0.67  % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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